Overview

This example illustrates how to plan a parallel count-outcome equivalence study with three treatment arms and three count endpoints. The arms are a test product (TEST) and two reference products (EU_REF and US_REF). We use three clinically interpretable, illustrative endpoint names: Exacerbations, Hospitalizations, and RescueEvents (rescue-medication events). These labels represent event counts collected over the same follow-up period. The general distributional assumptions used by all SimTOST outcomes are described in the companion vignette methodological_assumptions.Rmd.

The count module supports scalar or vector-valued endpoint inputs. A joint simulation can require equivalence for k of the m endpoints and can apply Bonferroni, Mielke’s strong k-out-of-m (adjust = "t"), or Šidák adjustment to the endpoint-wise one-sided significance level. For a k-of-m decision, the t-adjustment uses alpha / (m - k + 1) [@mielke_sample_2018]. The joint count kernel can also simulate correlated endpoints through the cor_mat argument.

Study assumptions

The assumed event rates are:

rate_list <- list(
  TEST = c(Exacerbations = 0.19,
           Hospitalizations = 0.13,
           RescueEvents = 0.08),
  EU_REF = c(Exacerbations = 0.20,
             Hospitalizations = 0.13,
             RescueEvents = 0.08),
  US_REF = c(Exacerbations = 0.21,
             Hospitalizations = 0.12,
             RescueEvents = 0.08)
)

comparisons <- list(
  EU_comparison = c("TEST", "EU_REF"),
  US_comparison = c("TEST", "US_REF")
)

lower_margin <- 0.80
upper_margin <- 1.25
# Five units of follow-up provide a realistic event-count scale for this
# illustrative example and allow the target power to be reached efficiently.
exposure <- 5

The rate-ratio equivalence interval is 0.80 to 1.25. We use a Poisson model for the primary example and a one-sided significance level of 0.05 for each TOST component.

Power for a fixed sample size

Before estimating sample size, power can be examined for each endpoint and comparison. Here we use 100 participants per treatment arm and a small number of simulations to keep the vignette fast.

fixed_power <- do.call(rbind, lapply(names(comparisons), function(comp) {
  arms <- comparisons[[comp]]
  do.call(rbind, lapply(names(rate_list[[arms[1]]]), function(endpoint) {
    result <- simPower(
      n = 100,
      distribution = "pois",
      rate_list = setNames(list(
        setNames(rate_list[[arms[1]]][[endpoint]], endpoint),
        setNames(rate_list[[arms[2]]][[endpoint]], endpoint)
      ), arms),
      list_comparator = setNames(list(arms), comp),
      list_lequi.tol = setNames(list(lower_margin), comp),
      list_uequi.tol = setNames(list(upper_margin), comp),
      exposure = exposure,
      dtype = "parallel",
      nsim = 1000,
      seed = 1234
    )
    data.frame(comparison = comp, endpoint = endpoint,
               power = result$power,
               power_LCI = result$power_LCI,
               power_UCI = result$power_UCI)
  }))
}))

fixed_power
#>      comparison         endpoint power    power_LCI   power_UCI
#> 1 EU_comparison    Exacerbations 0.000 0.0000000000 0.004770729
#> 2 EU_comparison Hospitalizations 0.000 0.0000000000 0.004770729
#> 3 EU_comparison     RescueEvents 0.000 0.0000000000 0.004770729
#> 4 US_comparison    Exacerbations 0.002 0.0003464932 0.008032515
#> 5 US_comparison Hospitalizations 0.000 0.0000000000 0.004770729
#> 6 US_comparison     RescueEvents 0.000 0.0000000000 0.004770729

Sample-size estimation for all comparisons and endpoints

We now estimate the smallest sample size per arm that reaches 80% power for each individual comparison and endpoint.

sample_size_results <- do.call(rbind, lapply(names(comparisons), function(comp) {
  arms <- comparisons[[comp]]
  do.call(rbind, lapply(names(rate_list[[arms[1]]]), function(endpoint) {
    result <- sampleSize(
      power = 0.80,
      distribution = "pois",
      rate_list = setNames(list(
        setNames(rate_list[[arms[1]]][[endpoint]], endpoint),
        setNames(rate_list[[arms[2]]][[endpoint]], endpoint)
      ), arms),
      list_comparator = setNames(list(arms), comp),
      list_lequi.tol = setNames(list(lower_margin), comp),
      list_uequi.tol = setNames(list(upper_margin), comp),
      exposure = exposure,
      dtype = "parallel",
      nsim = 1000,
      seed = 1234,
      lower = 10,
      upper = 2000
    )
    data.frame(comparison = comp, endpoint = endpoint,
               n_per_arm = result$n_per_arm,
               n_total_for_pair = result$n_total,
               achieved_power = result$power)
  }))
}))

sample_size_results
#>      comparison         endpoint n_per_arm n_total_for_pair achieved_power
#> 1 EU_comparison    Exacerbations       428              856          0.806
#> 2 EU_comparison Hospitalizations       522             1044          0.810
#> 3 EU_comparison     RescueEvents       846             1692          0.800
#> 4 US_comparison    Exacerbations       793             1586          0.815
#> 5 US_comparison Hospitalizations       903             1806          0.803
#> 6 US_comparison     RescueEvents       846             1692          0.800

stopifnot(all(sample_size_results$achieved_power >= 0.80))

For a simple conservative planning rule, select the maximum required sample size per arm across all six comparison-endpoint combinations:

required_per_arm <- max(sample_size_results$n_per_arm)
required_total <- 3 * required_per_arm

c(required_per_arm = required_per_arm, required_total = required_total)
#> required_per_arm   required_total 
#>              903             2709

The total is multiplied by three because the study has three treatment arms. This rule ensures that each individual comparison and endpoint has at least the target simulated power under its own assumptions. It is not a substitute for a multiplicity-adjusted joint power calculation.

Joint sample-size estimation with k = 3

The joint sample-size function receives all three arms, both comparison families, and all three endpoints at once. Here, k = 3 requires all three endpoints to demonstrate equivalence for every comparison, while the Bonferroni option adjusts across all six comparison-endpoint tests. The returned sample size is therefore based on one joint simulated success criterion rather than the maximum of separate searches.

endpoint_corr <- matrix(c(
  1.0, 0.40, 0.25,
  0.40, 1.0, 0.35,
  0.25, 0.35, 1.0
), nrow = 3, byrow = TRUE)

joint_result <- sampleSize(
  power = 0.80,
  distribution = "pois",
  rate_list = rate_list,
  list_comparator = comparisons,
  list_lequi.tol = list(
    EU_comparison = rep(lower_margin, 3),
    US_comparison = rep(lower_margin, 3)
  ),
  list_uequi.tol = list(
    EU_comparison = rep(upper_margin, 3),
    US_comparison = rep(upper_margin, 3)
  ),
  exposure = rep(exposure, 3),
  cor_mat = endpoint_corr,
  dtype = "parallel",
  nsim = 500,
  seed = 1234,
  lower = 10,
  upper = 3000,
  k = 3,
  adjust = "bonferroni"
)

joint_sample_size <- data.frame(
  n_per_arm = joint_result$n_per_arm,
  n_total = joint_result$n_total,
  achieved_power = joint_result$power,
  k = joint_result$k,
  adjustment = joint_result$adjust
)

joint_sample_size
#>   n_per_arm n_total achieved_power k adjustment
#> 1      1881    5643            0.8 3 bonferroni
stopifnot(all(joint_sample_size$achieved_power >= 0.80))

For a three-arm allocation, the reported total is three times the selected number per arm. Both comparison families share the simulated test-arm counts, and the endpoint correlation is generated through a Gaussian-copula count model. This is therefore a joint count simulation rather than a maximum of separate comparison-specific searches.

Why joint planning is important

The separate calculation above targets 80% power for each comparison-endpoint combination. That does not mean that the complete trial has 80% probability of passing all six requirements. For example, if two requirements each have 80% power and are independent, their joint success probability is only 0.80×0.80=0.640.80 \times 0.80 = 0.64.

The following comparison evaluates the separate result under the actual joint criterion. The joint calculations use Bonferroni adjustment across the six comparison-endpoint tests and require all three endpoints for both comparison families (k = 3). The independent-endpoint scenario uses an identity correlation matrix; the correlated scenario uses the matrix specified above.

joint_power_at_separate <- simPower(
  n = required_per_arm,
  distribution = "pois",
  rate_list = rate_list,
  list_comparator = comparisons,
  list_lequi.tol = list(
    EU_comparison = rep(lower_margin, 3),
    US_comparison = rep(lower_margin, 3)
  ),
  list_uequi.tol = list(
    EU_comparison = rep(upper_margin, 3),
    US_comparison = rep(upper_margin, 3)
  ),
  exposure = rep(exposure, 3),
  cor_mat = endpoint_corr,
  dtype = "parallel",
  nsim = 1000,
  seed = 1234,
  k = 3,
  adjust = "bonferroni"
)

joint_independent_result <- sampleSize(
  power = 0.80,
  distribution = "pois",
  rate_list = rate_list,
  list_comparator = comparisons,
  list_lequi.tol = list(
    EU_comparison = rep(lower_margin, 3),
    US_comparison = rep(lower_margin, 3)
  ),
  list_uequi.tol = list(
    EU_comparison = rep(upper_margin, 3),
    US_comparison = rep(upper_margin, 3)
  ),
  exposure = rep(exposure, 3),
  cor_mat = diag(3),
  dtype = "parallel",
  nsim = 500,
  seed = 1234,
  lower = 10,
  upper = 3000,
  k = 3,
  adjust = "bonferroni"
)

joint_comparison <- data.frame(
  approach = c(
    "Separate searches; joint power evaluated afterward",
    "Joint search; independent endpoints",
    "Joint search; correlated endpoints"
  ),
  n_per_arm = c(
    required_per_arm,
    joint_independent_result$n_per_arm,
    joint_result$n_per_arm
  ),
  joint_power = c(
    joint_power_at_separate$power,
    joint_independent_result$power,
    joint_result$power
  )
)

joint_comparison
#>                                             approach n_per_arm joint_power
#> 1 Separate searches; joint power evaluated afterward       903       0.159
#> 2                Joint search; independent endpoints      1916       0.800
#> 3                 Joint search; correlated endpoints      1881       0.800

The separate-search sample size is smaller because it guarantees only the individual 80% targets. In this example, its joint power is approximately 5% after the six-test Bonferroni adjustment, whereas the joint searches achieve the requested 80% trial-level power. This is the main advantage of joint planning: it answers the question that matters for the confirmatory trial, namely the probability that all required comparisons and endpoints succeed in the same simulated study. Positive endpoint correlation can reduce the joint sample size because endpoint successes tend to occur together, but it does not remove the need for a joint calculation.

Negative-binomial sensitivity analysis

If prior evidence suggests overdispersion, repeat the calculations with the negative-binomial model. The dispersion parameter controls the amount of overdispersion; larger values imply greater variability.

nb_sensitivity <- simPower(
  n = required_per_arm,
  distribution = "nbinom",
  rate_list = list(
    TEST = rate_list$TEST[["Exacerbations"]],
    EU_REF = rate_list$EU_REF[["Exacerbations"]]
  ),
  list_comparator = list(TEST_vs_EU = c("TEST", "EU_REF")),
  list_lequi.tol = list(TEST_vs_EU = lower_margin),
  list_uequi.tol = list(TEST_vs_EU = upper_margin),
  exposure = exposure,
  dtype = "parallel",
  dispersion = 0.10,
  nsim = 300,
  seed = 1234
)

nb_sensitivity
#> Fixed-sample-size power
#> Distribution: nbinom 
#> Sample size: 903 
#> Power: 0.2633 [0.2152, 0.3177]

Interpretation and limitations

This vignette demonstrates both a conservative and a joint endpoint workflow for a three-arm, three-endpoint count study using the current API. In the separate-search workflow, endpoint and comparison calculations are performed independently, whereas the joint workflow evaluates the required success event in the same simulated trial. The distributional and dependence assumptions are described in the companion methodological_assumptions.Rmd vignette.

For a confirmatory three-arm/three-endpoint trial, the statistical analysis plan should specify the familywise error strategy and joint success criterion.